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第12章 三相电路
一、选择题
如图12-1所示为对称三相电路,电源线电压U1=1OOV,线电流I1=2A,负载功率因数λ=cosφ=0.8(感性),功率表接法也如图所示,则此时功率表读数为( )。[上海交通大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image437.jpg?sign=1739533276-X5Zv0Cy0NSOJzHGoI3wkCLwpwBbSM20e-0-b9e748f32ecb49b5a1e6079b99fa2de9)
图12-1
A.208W
B.120W
C.173W
D.0
【答案】A
【解析】选为参考相量,
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image440.jpg?sign=1739533276-8ibUMsVzOMxs04q2uReAushx2g3o1yV7-0-6d1d861d63ab7bf1fe5e85f61afd3a1d)
二、填空题
1.在如图12-2所示的对称三相正弦交流电路中,所有三只安培表的读数都是10A,如果外加三相对称线电压保持不变,而将AB相负载断开,则电流表A1的读数为_____,电流表A2的读数为_____,电流表A3的读数为_____。[浙江大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image441.jpg?sign=1739533276-6kiwH9eKVEunHjoci1xvmoP1BEg7gOPf-0-f69398c5a0ceabaea26f5e39747c22e7)
图12-2
【答案】5.77A; 5.77A; 10A
【解析】按一般正弦稳态电路分析方法即可得出结果。
2.图12-3所示三相对称电路中开关S合上时电流表A1的读数是A,则开关S合上时电流表A2的读数是( );A3的读数是( );开关S断开时电流表A1的读数是( );A2的读数是( );A3的读数是( )。[华南理工大学2010研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image443.jpg?sign=1739533276-eYHIp76JdWqnjFExjRyNaGnCceCZyHMW-0-ac1c8f4a79b66f5b159dcef2d9c4b15a)
图12-3
【答案】;
;
;10A;10A
【解析】根据三相电路的对称性,在开关闭合后,三表读数是相同的,即都是;在开关打开之后,
读数不变认为
,
和
的电流表读数变化,线电流变为相电流,为10A。
3.某三角形联接的电力负载,线电压、
及
严重不对称且含有5、7次谐波,该三相负载线电压的零序分量为( )。[华南理工大学2009研]
【答案】
【解析】将不对称的三相线电压分解为三组对称的相量,分别为正序分量、负序分量和零序分量。由于三相线电压中各相对应的正序分量相量和为0、负序分量相量和为0,并且各谐波分量只含有交流分量(即正序、零序分量),无零序分量。则三相线电压的相量和即为三倍的零序分量。即有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image452.png?sign=1739533276-AB3za7JCDzf5q4HJnrtgOicO5fLsbWGC-0-3fd15f1a53c5d2f3d590b352e6f19f43)
4.如图12-4所示对称三相电路中,已知星形连接负载(复)阻抗Z=5+j8.66Ω,若已测得电路无功功率
图12-4
【答案】由Z=5+j8.66Ω可得阻抗角为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image455.jpg?sign=1739533276-PFw6epUWIqSRXsw78kysysYy5CaU0LdI-0-fb2b3b3583ac51abd5d1d0e75057a28d)
于是有功功率为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image456.jpg?sign=1739533276-fz8tOryeUMcfjYDq7RdILxavE8wWcAMA-0-5cefa04c22d0b5f85c783bd6e979aa4e)
三、计算题
1.线电压为
的三相电源上接有两组对称三相负载:一组是三角形联结的电感性负载,每相阻抗
;另一组是星形联结的电阻性负载,每相电阻
,如图12-5所示。试求:(1)各组负载的相电流;(2)电路线电流;(3)三相有功功率。[西南大学2012研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image461.jpg?sign=1739533276-dbYztNWCjXxegqtPNzwQvqgPfA1cAPOu-0-861f2fbf5079529c7c0dd9b7faef39df)
图12-5
解:设。
(1)对于星形负载,线电流等于相电流,为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image463.png?sign=1739533276-inIkN0tNQOMIn3bLHFahwDJI4CavAieo-0-780e3940c12b391ab8af8af9eaf7ec27)
星形负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image464.png?sign=1739533276-D4woIZJlo1dVg1ryWrmcI1qTRgjKXmM1-0-6a0d809f0667b08e6464835788c78271)
对于三角形联结的负载,相电流为线电流的倍。将三角形联结等效为星形联结。得相电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image466.png?sign=1739533276-ZAscCfO0k4bXMGdWWDWT7UjYzMxzaHBM-0-e99ceeb8cdf9868edcee37bd7f648cfd)
线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image467.png?sign=1739533276-pUtqjbIAHxJKauPdzim31IykyN7Qwa13-0-e5d0bb452859834003296e36c3fc24af)
(2)电路线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image468.png?sign=1739533276-nhrSOv7mOUPwTwStO5yV4fVCuKkmJXeA-0-58e36c4fcfd83dbe3360fc4c5ba9e425)
(3)三角形联结负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image469.png?sign=1739533276-Irx9hO7f5Lm2yxd1sKG1LOKMcAe6wkT1-0-9601bac8fd96a0ba42a46eee5f016448)
则总三相有功功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image470.png?sign=1739533276-Ao3i51dF6MRAQOnFJKUr32TXOBevMObV-0-51f5d671609b4126fefd928dedc44178)
2.图12-6(a)所示的对称三相电路中,三相电源线电压U1=300V,三相角接负载阻抗(容性)吸收功率P=4500W,三相电源供出的功率PS=7200W,线路阻抗Z1=(3+j3)Ω。试求线电流I1和负载阻抗Z。[天津大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image471.jpg?sign=1739533276-pnz8pZ30lOjYAyaKQTLgzFvDXwJ14IbW-0-5526ec5c615b38cec2c49adfa28ce874)
图12-6
解:由已知条件,线路阻抗消耗的平均功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image473.png?sign=1739533276-MFuCHy9USLPQlLhGRYG4VU8vlTWrlER1-0-15dc2c201405f241979aa025e216049f)
则三相电路的线电流为:
将△形负载等效成Y形负载,并取其一相得图(b)所示电路,其中:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image475.jpg?sign=1739533276-kTFVJIxWKQVnhDc4dSXERn4ccc8cbKGy-0-266fd7e84740d672d88157d6d1d2d148)
在图(b)中,相电流等于原电路的线电流。
再由负载消耗功率可知实部为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image477.jpg?sign=1739533276-S4TLkFhyKcqt5qWb8BdgAo9dVXZEzqvS-0-67e1cf52794fb8421b001cd0613704c0)
由题知,负载阻抗为容性,则有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image478.jpg?sign=1739533276-079pYCLvyaaIeia5YAv5q97zZnuF14oY-0-d0cb8a5185a025c43ee989ebe0f33219)
解得:XY=9Ω
则△形负载阻抗为:。
3.如图12-7所示对称三相电路中,对称三相电源频率为50Hz,线电压为380V,对称三相负载Z=(18+j24)Ω,对称三相电容负载C=58μF。试求:(1)各线电流;(2)电源发出的复功率。[北京交通大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image480.jpg?sign=1739533276-IElREmJsPuiMNt120XJJZ8DUAyrT9QKm-0-8c080f91f5c613d5408ff1b7a10595a8)
图12-7
解:(1)已知电源线电压为380V,可知相电压(这里设定A相相电压相角为):
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image482.png?sign=1739533276-m8VnEEPxsexYBt7k7BWCrcbXsjZJBvDw-0-7b20ac296f6fc05a41f18d5a4eed7b64)
V
V
A
A
A
再由对称性可得、
:
A
A
(2)三相电源的复功率为
V·A
4.图12-8中A、B、C为对称三相电源,已知
图12-8
解:因为A、B、C为对称三相电源,所以
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image495.jpg?sign=1739533276-l12cjZ8kkwpmpiSsoQp9rKmMIr1uJhaq-0-2a5b672a9ffaa09cf88dbba4b7c622d5)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image496.jpg?sign=1739533276-lAfEdC1Hno5Jw2l9P8BD85fzG5VBM4ht-0-3fe6cc119a41099f36f16cc057f9a9d9)
先求阻抗Z的模值:
由题、
都闭合时,三个电流表读数均为5A,则有:
,解得
=132
。
(1)当开关S1闭合、S2断开时,A1、A2、A3的读数分别为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image502.png?sign=1739533276-ntO17w9zVBbySNtNnHmxy7Q7SxURCNeQ-0-d4d251d901e6e3bcf59a9a44ed59fbe7)
由对称性知A
不变,即
A
(2)当开关S1断开、S2闭合时,A1、A2、A3的读数分别为:
A
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image507.png?sign=1739533276-jK1bRgQd7SKEF95otyUOtZmjimuFsrPK-0-a33f914741db23e84582a8ff451abb86)
A
5.如图12-9所示电路中,已知对称三相电压源线电压为380V,两组对称负载。第一组负载均为,第二组负载均为
,求:(1)电流表A1、A2、A3的示数;(2)当第二组A相负载发生短路故障后,电流表A1、A2、A3的示数;(3)当第二组A相负载发生断路故障后,电流表A1、A2、A3的示数。[北京交通大学2010研]
图12-9
解:(1)进行变换,得
。令
。
对于电流表A1:,故A1的示数为
A。
对于电流表A3:由,故A3的示数为11A。
对于电流表A2:,又
,
,
,所以
,故A2的示数为
A。
(2)对于电流表A3:,故A3的示数为
A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A1:设,则
,
,由此可得
,故
。
又,所以:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image533.png?sign=1739533276-6qc7xTbmMEmW6d9xz066k18CoOWADrjQ-0-31450d7680f3e526e1a08882e9f07754)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image535.png?sign=1739533276-Pvp1AZgrrnyAH7QP8oKcPFagZG1VqQhG-0-3cc8e57fa74c32ce5507a814185aa12a)
因此,A1的示数为65.1A。
(3)对于电流表A1:,故A1的示数为46.5A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A3:,故A3的示数为9.5A。
6.图12-10所示三相对称电路,已知电压表的读数为,负载阻抗
,线路阻抗
,求图中电流表的读数和线电压UAB。[北京科技大学2011研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image542.jpg?sign=1739533276-TaVQ0GMKqvVwIjcecrarbT80FfQkuu5A-0-f2c7c94b62453b1ee1169e1fe048635c)
图12-10
解:(1)根据对称线电压和对称相电压之间的关系,可得对称相电压
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image543.png?sign=1739533276-Y90OOGjYkaZQnoth5y3cghixIxdn71cb-0-e8506e0c60a5bca7bb25cedf71a771a5)
则有
A
则电流表的示数为16.67A
(2)则
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image546.png?sign=1739533276-8MPIu7OP2T4u3zzx9MsDnH2h3kx0M6y5-0-91118ac2f09239b69bc4598c574d538c)
7.已知如图12-11所示电路中对称三相电源线电压V,阻抗Z1=50+j50Ω,Z2=20Ω,Z3=40+j80Ω,中线电阻R=3Ω。
(1)求图示功率表的读数;
(2)求A相电源uA发出的有功功率和无功功率。[清华大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image548.png?sign=1739533276-7vzKNwLJGNdmwIE4K26KXYBqMNCt1uxg-0-7455ffeca8270cdc0c67ea9260cad396)
图12-11
解:(1)题图所示电路中,阻抗直接并接在A相电源上,对功率表的读数没有影响。求功率表读数电路如图12-12(a)所示,其单相计算电路如图12-12(b)所示。
图(a) 图(b)
图12-12
则可得:
V
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image552.png?sign=1739533276-vLKMlmfgc1e8sJbbbcprYKfUvWHRXZol-0-395a17c3ddcb420d47841411c5dee29e)
功率表的读数为:。
(2)A相电源发出的有功功率:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image554.png?sign=1739533276-7tEtPNuzfAMFFE03zPQM6kFWik4bVLCl-0-ce3cc1d63b8754ed103c6a0b6c27475d)
8.如图12-13所示三相四线制电路中,接有两组对称三相负载和一个单相负载。已知对称三相电源相电压为220V,第一组对称三相负载、
、
的大小。[同济大学2009研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image562.png?sign=1739533276-sicjekkUJ1e3Wm6oaD4iHOyRqg44asUW-0-5fbf9bf4dbe9dc27daafce98166fae0e)
图12-13
解:设A相电压为,则第一组对称三相负载的电流
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image564.png?sign=1739533276-2DyHHT7Gq5A1QCa88wBuf9JNu4nCT9v9-0-f470e1c8b81ea64198e76628280b6185)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image565.png?sign=1739533276-4R6gv7ryQShSeDYFyAYVJgMFjvKu7D03-0-92f571d3eb7b68d2eaee9e41212f04d9)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image566.png?sign=1739533276-pDNnVQz25UQNWEtqZ1ROP5f0NL7sIRGZ-0-4d1251dec942eb2a713d3c420d6d2c87)
假设负载为星型连接,则:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image567.png?sign=1739533276-zN72qiKQ8kCbbSLSCKLw0k279zdWXbxP-0-a962b44668ff296b8beb07c3711385fd)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image568.png?sign=1739533276-YAgHqxki6vneslJzhsAOWuEcvCGPKasV-0-a51f8ae8c4b8a9b37b9ff8a66d48fd20)
故第二组对称三相负载的电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image569.png?sign=1739533276-sa6Lr9qy2tYNCBKca8jaLawpSNT1IrRK-0-75ff3d33ad4c61466e1c3746110cce4c)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image570.png?sign=1739533276-7YWtmuL2jK8euZgmKhAz1pAtl3QqFmT9-0-903222dd33e551f0e30a9691a993deb6)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image571.png?sign=1739533276-fLihLFtdZgHtY4ESqdmHt5vFvtOEnee3-0-1c244f31620cad99a47138aed101b0ea)
单相负载的电流:。
电源端线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image574.png?sign=1739533276-8e9KWaEcIdwY86jarJzYrGQxCTud0S6r-0-732e801206e8aa2863f2d1a741d4eaa6)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image575.png?sign=1739533276-Txvl6spQqpxY4MYYT5ws1gk07TOGxtGP-0-90e25749a42a43ed742813e859a73e82)
因此:,
,
。